[no subject]

What's strange about it. [ is a commutative operator, so a[i] and i[a]
represent the same thing i.e. *(a+i). The reason the compiler doesn't complain
is that printf takes a void pointer in that spot, so since the result is a
char *, no worries.

BAJ
> 
> 	bjorn
> 
> --------------------------------------------------
> 
> /* Find the strangeness! Spotted on kuro5hin... */
> #include <stdio.h>
> 
> char *foo[] = {"what", "the", "heck", "is", "this"};
> 
> int main(int argc, char **argv)
> {
>   int j=2;
>   printf("Test: %s\n", j[foo]);
>   return 0;
> }
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> Ale mailing list
> Ale at ale.org
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